CentOS查看版本号
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CentOS查看版本号，最合适的命令为： cat /etc/redhat-release 以下为测试过程： 1.cat /etc/redhat-release [root@localhost ~]# cat /etc/redhat-release CentOS Linux release 7.2.1511 (Core) 2.lsb_release 命令没找到 3.uname -a [root@localhost ~]# uname -a Linux localhost.localdomain3.10.0-327.el7.x86_64 #1 SMP Thu Nov 19 22:10:57 UTC 2015 x86_64 x86_64 x86_64GNU/Linux 4.cat /proc/version [root@localhost ~]# cat /proc/version Linux version 3.10.0-327.el7.x86_64(builder@kbuilder.dev.centos.org) (gcc version 4.8.3 20140911 (Red Hat 4.8.3-9)(GCC) ) #1 SMP Thu Nov 19 22:10:57 UTC 2015
如何查看已安装的CentOS版本信息： 1)[root@localhost ~]# cat /proc/version Linux version 2.6.18-194.el5 (mockbuild@builder10.centos.org) (gcc version 4.1.2 20080704 (Red Hat 4.1.2-48)) #1 SMP Fri Apr 2 14:58:14 EDT 2010 2) [root@localhost ~]# uname -a Linux localhost.localdomain 2.6.18-194.el5 #1 SMP Fri Apr 2 14:58:14 EDT 2010 x86_64 x86_64 x86_64 GNU/Linux 3) [root@localhost ~]# uname -r 2.6.18-194.el5 2. 查看linux版本： 1) 列出所有版本信息, [root@localhost ~]# lsb_release -a LSB Version: :core-3.1-amd64:core-3.1-ia32:core-3.1-noarch:graphics-3.1-amd64:graphics-3.1-ia32:graphics-3.1-noarch Distributor ID: CentOS Description: CentOS release 5.5 (Final) Release: 5.5 Codename: Final 注:这个命令适用于所有的linux，包括RedHat、SUSE、Debian等发行版。 2) 执行cat /etc/issue,例如如下: [root@localhost ~]# cat /etc/issue CentOS release 5.5 (Final) Kernel r on an m 3) 执行cat /etc/redhat-release,例如如下: [root@localhost ~]# cat /etc/redhat-release CentOS release 5.5 (Final) 查看系统是64位还是32位: 1、getconf LONG_BIT or getconf WORD_BIT [root@localhost ~]# getconf LONG_BIT 64 2、file /bin/ls [root@localhost ~]# file /bin/ls /bin/ls: ELF 64-bit LSB executable,AMD x86-64,version 1 (SYSV),for GNU/Linux 2.6.9,dynamically linked (uses shared libs),stripped 3、lsb_release -a [root@localhost ~]# lsb_release -a LSB Version: :core-3.1-amd64:core-3.1-ia32:core-3.1-noarch:graphics-3.1-amd64:graphics-3.1-ia32:graphics-3.1-noarch Distributor ID: CentOS Description: CentOS release 5.5 (Final) Release: 5.5 Codename: Final 4、或者是使用查看文件的方法。 vim /ect/issue （编辑：莱芜站长网） 【声明】本站内容均来自网络，其相关言论仅代表作者个人观点，不代表本站立场。若无意侵犯到您的权利，请及时与联系站长删除相关内容! |
