| 
                         系统当前时间是多少周,就是是今年的第几个星期  <div class="codetitle"><a style="CURSOR: pointer" data="73724" class="copybut" id="copybut73724" onclick="doCopy('code73724')"> 代码如下:<div class="codebody" id="code73724">  select to_char(sysdate,'ww'),to_char(sysdate,'iw') from dual; select to_char(sysdate,'ddd') from dual; select TRUNC(SYSDATE,'MM') from dual;1)
  ww的算法为每年1月1日为第一周开始,date+6为每一周结尾 例如:20050101为第一周的第一天,而第一周的最后一天为20050101+6=20050107   公式: 每周第一天 :date + 周  7 - 7  每周最后一天:date + 周  7 - 12)iw的算法为星期一至星期日算一周,且每年的第一个星期一为第一周, 例如:20050101为星期六,所以用iw的算法是前年的53周,而20050103之后才是第一周的开始。   公式: 每周第一天 :next_day(date) + 周  7 - 7每周最后一天:next_day(date) + 周  7 - 13)其它:   A、查今天是 "本月" 的第几周  SELECT TO_CHAR(SYSDATE,'WW') - TO_CHAR(TRUNC(SYSDATE,'MM'),'WW') + 1 AS "weekOfMon" from dual;  或  SELECT TO_CHAR(SYSDATE,'W') AS "weekOfMon" from dual;   B、查今天是 "今年" 的第几周  select to_char(sysdate,'ww') from dual;  或  select to_char(sysdate,'iw') from dual; 统计哪年哪个星期的哪一天: <div class="codetitle"><a style="CURSOR: pointer" data="65438" class="copybut" id="copybut65438" onclick="doCopy('code65438')"> 代码如下:<div class="codebody" id="code65438"> int year=2011;  int week=1;  Calendar calFirstDayOfTheYear = new GregorianCalendar(year,  Calendar.JANUARY,1);  calFirstDayOfTheYear.add(Calendar.DATE,7 * (week-1));  int dayOfWeek = calFirstDayOfTheYear.get(Calendar.DAY_OF_WEEK);   Calendar calFirstDayInWeek = (Calendar)calFirstDayOfTheYear.clone();  calFirstDayInWeek.add(Calendar.DATE,  calFirstDayOfTheYear.getActualMinimum(Calendar.DAY_OF_WEEK) - dayOfWeek);  Date firstDayInWeek = calFirstDayInWeek.getTime();  System.out.println(year + "年第" + week + "个礼拜的第一天是" + ReportDateUtil.getFromatDay().format(firstDayInWeek));  Calendar calLastDayInWeek = (Calendar)calFirstDayOfTheYear.clone();  calLastDayInWeek.add(Calendar.DATE,  calFirstDayOfTheYear.getActualMaximum(Calendar.DAY_OF_WEEK) - dayOfWeek);  Date lastDayInWeek = calLastDayInWeek.getTime();  System.out.println(year + "年第" + week + "个礼拜的最后一天是" + ReportDateUtil.getFromatDay().format(lastDayInWeek));
                          (编辑:莱芜站长网) 
【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! 
                     |